Suggested: (x-4y-9)dx+(4x+y-2)dy=0 - (1+x^4)dy+x(1+4y^2)dx=0 y(1)=0 - x dx+(x^2y+4y)dy=0 y(4)=0 - y''-4y'+4y=0 y1=e^2x - y''-4y'+4y=0 - x2+y2+22x-4y-100=0 x2+y2-22x+4y+100=0 - (x^2+2xy-4y^2)dx-(x^2-8xy-4y^2)dy=0 - solve graphically 3x-4y+3=0 and 3x+4y-21=0 - find the distance between the lines 3x-4y+7=0 and 3x-4y+5=0 - solve y''+4y'+4y=4cosx+3sinx y0=0 y'0=0 - 4y'+4y=0 Browse related:
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