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Suggested: cotx cot2x-cot2x cot3x-cot3x cotx=1 - prove that cotx cot2x-cot2x cot3x-cot3x cotx=1 - prove that cotx.cot2x−cot2x.cot3x−cotx.cot3x=1 - cotx  cot2x  cot2x  cot3x  cot3x  cotx=1cat     

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