Suggested: x+1/x=3 then x2+1/x2= - (1-x2)d2y/dx2+xdy/dx-y=x(1-x2)3/2 - 4 x+1/x+1-3=12/x2-1 - if x+1/x=3 find the value of x2+1/x2 - 2x+3(-x2-1)=- 3x2+2x-1)-3x+2) - 2(x-3)2-3(x+1)2+(x-5)(x-3)+4x2-5x+1)=4x 2-12 - x3+x+1/x2-1 - integration of x3+x+1/x2-1 - find the hcf of x3-x2+x-1 and x4-1 - determine whether (x+1) is a factor of x3-x2-x+1 - x2 d2y/dx2-2x(1+x)dy/dx+2(1+x)y=x3 - x3+x+1 x2 1 Browse related:
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