Suggested: (1+cota+tana)(sina-cosa)/sec^3a-cosec^3a - (1+cot theta-cosec theta)(1+tan theta+sec theta)=2 - (1+cot theta+tan theta)(sin theta-cos theta) - (1+cot^(2)theta)(1-cos^(2)theta)= - (1+cota)(1+cotb)=2 - (1+cota+tana)(sina-cosa)=sinatana-cotacosa - (1+cota-coseca)(1+tana+seca)=2 - (1+cot-cosec)(1+tan+sec)=2 - (1+cota+tana)(sina-cosa) - (1+cot+tan)(sin-cos)/sec^3-cosec^3 - (1+cotx-cosecx)(1+tanx+secx)=2 - (1+cota+tana)(sina-cosa)/sec^3a-cosec^3a=sin^2a cos^2a - (1+cot^(2)theta)/(1+tan^(2)theta) का मान होगा - (1+cot2a)sin2a=1 - (1+cot Browse related:
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