Suggested: 1+sin2x formula - 1+sin2x maclaurin series - 1+sin2x - 1+sin2x-cos2x/1+sin2x+cos2x=tan x - 12. sin2)6x-sin2)4x=sin2x sin10x - 1-cos2x+sinx/sin2x+cosx - 1-cos2x/sin2x - 1/sin2x integration - 1/sin2x cos2x integral - 1-sin2x/1+sin2x=tan^2(pi/4-x) - 1/sin2x.cos2x ka integration - 1/sin2x cos2x - cosx-sinx/1+sin2x - integration of cosx-sinx/1+sin2x - 1+sin2x Browse related:
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