Suggested: 1+tan2x - 1+tan2x=sec2x - 1-2sen2x=1-tan2x/1+tan2x - 1+tan2x=1/cos2x - tan 4x=4tanx(1-tan2x) - tan 2x=2tanx/1-tan2x - prove that sin2x=2tanx/1+tan2x - sec8x-1/sec4x-1=tan8x/tan2x - sec22x=1-tan2x - tan2x/1+sec2x=tanx - tanx+tan2x+tanx tan2x=1 - tan2x tanx=1 - (1-sen2x)(1+tan2x)=1 - (1+tan2x)cosx=secx - 1+tan2x Browse related:
privacy contact
Copyright 2017 bapse
bapse is powered by Google and Youtube technologies
Thank you, for using bapse.
This site was designed and coded by Michael DeMichele,
and is being used as a portfolio demonstration. View more.