Suggested: 1/3 x+1+1/x+1-1/(3 x+1)(x+1) - find the domain of the function f(x)=x^2+2x+1/x^2-8x+12 - show that the middle term in the expansion of (x-1/x)^2n is 1.3.5 - 1/(x-1)(x-2)+1/(x-2)(x-3)=2/3 - 1-x/1+x integration - 1 x 1 x - 1/x-1/x+b=1/a-1/a+b - 1+x/1+x^2 integral - 1+x/1-x derivative - 1 x 1 x 2 - (x+m)(x+1)-(x+1)(x-n) - x+1/x=3 then x5+1/x5= - (2x-1)(x-3)=(x+5)(x-1) - 1/x+4-1/x-7=11/30 - 1 x 1 x Browse related:
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