Suggested: 16(3x-5)-10(4x-8)=40 - 3x/2-5y/3=-2 x/3+y/2=13/6 by substitution method - find the term independent of x in the expansion of (3/2x^2-1/3x)^6 - 2x+3y=17 3x-2y=6 graph - 3x/2-5y/3=-2 x/3+y/2=13/6 by elimination method - 3x+y=12 x+y=6 - simplify 1/x2-5x+6+1/x2-3x+2-1/x2-8x+15 - 2x+3y=16 3x-2y=0 - x-2 x+2-16/3x+5=3-7/2x - 4*16 decoder using 3x8 decoder - x-y=8 3x-3y=16 - 3x-2y=12 4x-5y=16 - 16(3x Browse related:
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