Suggested: 2(3x+1)2-8=0 - (x-1)(x-2)(3x-2)(3x+1)=21 - 5x-2(2x-7)=2(3x-1)+7/2 solve - x2+3x+1=(x-2)2 - find the discriminant of the equation 3x^2-2x+1/3=0 - 1/3x+y+1/3x-y=3/4 1/2(3x+y)-1/2(3x-y)=-1/8 - find the term independent of x in the expansion of (3/2x^2-1/3x)^6 - 3x+y=1 (2k-1)x+(k-1)y=2 k+1 - divide 2x2+3x+1 by x+2 - 3x+2ky=2 and 2x+5y+1=0 - 5x-2/1+2x+3x^2 - 2x-1/3x=2 হলে 3x-1/2x= - 6(2x^2-3x-2) 8(4x^2+4x+1) 1 2(2x^2+7x+3) - 3(3x-1/2x+3)-2(2x+3/3x-1)=5 - 2(3x+1)2 Browse related:
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