Suggested: 2(ab+bc+ca) - show that r1/bc+r2/ca+r3/ab=1/r-1/2r in telugu - a+b+c=9 and ab+bc+ca=23 find a3+b3+c3-3abc - if a+b+c=9 and ab+bc+ca=26 find a2+b2+c2 - ab=100 bc=200 ac=300 a+b+c= - a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca) - a2+b2+2(ab+bc+ca) - a^2+b^2+c^2-ab-bc-ca - (a+b+c)2=a2+b2+c2+2(ab+bc+ca) - if a^p=bc b^q=ca and c^r=ab prove that pqr=p+q+r+2 - if a+b+c=1 ab+bc+ca=2 - if ab+bc+ca=0 then find the value of 1/a^2-bc+1/bc^2-ca+1/c^2-ab - 2(ab+bc+ca) Browse related:
privacy contact
Copyright 2017 bapse
bapse is powered by Google and Youtube technologies
Thank you, for using bapse.
This site was designed and coded by Michael DeMichele,
and is being used as a portfolio demonstration. View more.