Suggested: y''+2y'-24y=16-(x+2)e^4x - x-y=2 3x+2y=16 - x-3y+2z=1 3x+2y+z=16 x-2y+3z=8 - 5x+4y=35 2x+2y=16 - solve x+y+z=5 2x-y+z=9 x-2y+3z=16 - x+y+z=5 2x-y+z=9 x-2y+3z=16 in tamil - 2x+y+z=10 3x+2y+3z=18 x+4y+9z=16 gauss elimination method - 2x+3y=16 3x-2y=0 - x+y+z=5 2x-y+z=9 x-2y+3z=16 - 3x-2y=3 2x+y=16 - 2x+y+z=10 3x+2y+3z=18 x+4y+9z=16 gauss jordan method - gauss jordan method x+2y+z=8 2x+3y+4z=20 4x+3y+2z=16 - 2x+y=160 4x+2y=300 - (1+2 x)^2d^2y/dx^2-6(1+2 x)dy/dx+16 y=8(1+2x)^2 - 2x+2y=16 Browse related:
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