Suggested: prove that x^2-y^2+4z^2+4xy+2yz+6xz is indefinite - (x+2y+4z)2 - test the consistency and solve 2x-y+3z=8 x-2y-z=-4 3x+y-4z=0 - 2x-3y+5z=11 3x+2y-4z=-5x+y-2z=-3 - solve the system of equations 4x+2y+z+3w=0 6x+3y+4z+7w=0 2x+y+w=0 - test for consistency and solve x+2y+3z=14 4x+5y+7z=35 3x+3y+4z=21 - 4x+2y+z+3w=0 6x+3y+4z+7w=0 2x+y+w=0 - x-3y+4z y-2x-8z 5x-2y-3z - find the maximum value of u=x^2y^3z^4 if 2x+3y+4z=a - 2y+4z=2 Browse related:
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