Suggested: f(x)=2x+3 g(x)=1-2x y(x)=3 x prove that fo(goh)=(fog)oh - 2x/x-3+1/2x+3+3x+9/(x-3)(2x+3)=0 - 2x+5y=1 2x+3y=3 - 3(3x-1/2x+3)-2(2x+3/3x-1)=5 - 6(2x^2-3x-2) 8(4x^2+4x+1) 1 2(2x^2+7x+3) - solve for x 2(2x-1/x+3)-3x+3/2x-1)=5 - (2x-1)/3(3x-2)/4-(2x)/5 - integration of 3x+1/2x^2-2x+3 - (4x-3/2x+1)-10(2x+1/4x-3)=3 - x+2y-z=3 3x-y+2z=1 2x-2y+3z=2x-y+z=-1 - solve for x 2x/x-3+1/2x+3+3x+9/(x-3)(2x+3)=0 - integral x^2+2x-1/2x^3+3x^2-2x - solve (2x-1)(x+3)(x-2)(2x+3)+20=0 - 2x/x-3 + 1/2x+3 + 3x+9/(x-3)(2x+3) - 3(2x 1)= 2x+3) Browse related:
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