Suggested: 3(x-2)=4x+3) - 3(x-2)=4(-x+3) - 2(x-1)-3(x-2)=4(x-3)+5(x-4) - (x-3)(x-4)=34/33^2 - 1/2(3 x/5+4)≥1/3(x-6) - x-1/x-2+x-3/x-4=10/3 - 3/4(7x-1)-(2x-1-x/2)=x+3/2 - show that (x-2) (x+3) and (x-4) are factors of x3-3x2-10x+24 - x+2/6-(11-x/3-1/4)=3x-4/12 - 1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)=1/6 - (x-2)2+x(x-3)=3(x+4)(x-3)-(x+2)(x-1)+2 - x+3/2-3x+1/4=2(x-2)/3-2 - if u=x+3y^2z^3 v=4x^2yz xy=2 z^2-xy - express f(x)=x^4+x^3+2x^2-x-3 in terms of legendre polynomials - 3(x 2)=4( x+3) Browse related:
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