Suggested: 3(x-3)=15 - find the term independent of x in the expansion of (3/2x^2-1/3x)^15 - find the value of x^3+y^3+z^3-3xyz if x2+y2+z2=83 and x+y+z=15 - resolve (x^(2)+13x+15)/((2x+3)(x+3)^(2)) into partial fractions - x^2+13x+15/(2x+3)(x+3)^2 - 4x/3-3/5=7/15+x/10 - 2(3-x)=3(x-4)+15 - x2+13x+15/(2x+3)(x+3)2 - 3(x 3)=15 Browse related:
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