Suggested: prove that a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab-bc-ca) - if a+b+c=15 and a2+b2+c2=83 find a3+b3+c3-3abc - if a+b+c=9 and a2+b2+c2=35 find the value of a3+b3+c3-3abc - if a+b+c=0 then show that a2(bc)+b2(ca)+c2(ab)+3abc=0 - 3abc=(a+b+c)(a2+b2+c2 Browse related:
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