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Suggested: 3x+5y=0 - 3x-5y-4=0 and 9x=2y+7 by substitution method - 3x-5y+1=0 2x-y-3=0 graph - 3x-5y-4=0 and 9x=2y+7 vilopan vidhi - 3x-5y-4=0 9x=2y+7 - 3x-5y-4=0 and 9x=2y+7 pratisthapan vidhi - 5x-8y+1=0 3x-24/5y+3/5=0 - show that the straight lines 3x-5y+7=0 and 15x+9y+4=0 are perpendicular - 3x+2ky=2 and 2x+5y+1=0 - solve by substitution method 3x-5y-4=0 and 9x=2y+7 - 6x-3y=-10 3x+5y-8=0 - 3x+5y=0               

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