Suggested: cos2x=1-2sin^2x - cos2x=1/2 - sin8x-cos8x=(sin2x-cos2x)(1-2sin2x cos2x) - 1/cos2x(1-tanx)^2 - lim x tends to pi/2 1+cos2x/(pi-2x)^2 - sin8x-cos8x/1-2sin2x cos2x - (d^3+d^2-d-1)y=cos2x - sin2x=1-cos2x/2 - prove cos2x=1-tan^2x/1+tan^2x - lim 1-cos2x/x^2 - prove that cos2x=2cos^2x-1 - cos2x=2cos^2x-1 - integrate 1/cos2x(1-tanx)^2 - integration of 1-cos2x/2 - cos2x=1 2 Browse related:
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