Suggested: y con dinero y sin dinero - if u=sin^-1(x/y)+tan^-1(y/x) prove that x dy/dx)+ydu/dy)=0 - x=a(theta+sin theta) y=a(1-cos theta) then dy/dx - dy/dx=sin(x+y) - dy/dx+ycosx+siny+y/sinx+xcosy+x=0 - dy=y(sin Browse related:
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