Suggested: tan 4x=4tanx(1-tan^ 2x)/1-6tan^ 2x+tan^ 4 x - (1+y2)dx=(tan-1y-x)dy - if u=tan^-1(x^3+y^3/x-y) - u=sin^-1(x/y)+tan^-1(y/x) - u=x^2 tan^-1(y/x)-y^2 tan^-1(x/y) - sin(tan^-1(x)) - y=(tan^-1 x)^2 derivative - u=x+y/1-xy v=tan^-1x+tan^-1y - tan inverse 1-x/1+x=1/2 tan inverse x - (1+y^2)+(x-e^tan^-1y)dy/dx=0 - expand tan inverse x in powers of x-1 - integral of tan^-1 x dx - separate into real and imaginary parts of tan-1(x+iy) - nth derivative of tan inverse 2x/1-x^2 - tan x= 1 Browse related:
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