Suggested: x+3y=15 - x+3y=15 3x+6y=30 - x-3y-7=0 3x-3y-15=0 - x-3y=7 3x-3y=15 - x-3y-7=0 3x-3y-15=0 by substitution method - x-3y-7=0 3x-3y-15=0 by cross multiplication - if 3x+2y=10 and 2x+3y=15 find the value of x+y - solve 1/2x+1/4y-1/3z=1/4 1/x=1/3y 1/x-1/5 y+4/z=2 2/15 - 4x-2y+6z=8x+y-3z=-1 15x-3y+9z=21 - x/6+y/15=4x/3y/12=19/4 - test the consistency and solve 4x-2y+6z=8x+y-3z=-1 15 x-3y+9z=21 - (4x^3y-15x^2-y)dx+(x^4+3y^2-x)dy=0 - 5 x/12-y=9 x-3y/4=15 - solve by cramer's rule 4x-2y+6z=8x+y-3z=-1 15x-3y+9z=21 - x+3y=15 Browse related:
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